The character special files /dev/random and /dev/urandom (present since Linux 1.3.30) provide an interface to the kernel's random number generator. The file /dev/random has major device number 1 and minor device number 8. The file /dev/urandom has major device number 1 and minor device number 9. The random number generator gathers environmental. Dec 29, 2015 If you run 'make load' or reboot, the kernel module will be loaded into the running kernel, but now will replace the /dev/urandom device file. The old /dev/urandom device is renamed (keeping it's inode number). This allows any running process that had /dev/urandom to continue running without issues. If your system has a means to generate random numbers involving not only a software algorithm (like the /dev/urandom devices in Unix), then:. Show how to obtain a random 32-bit number from that mechanism. You can use od to get numbers out of /dev/random and /dev/urandom. For example, 2 byte unsigned decimal integers, $ od -vAn -N2 -tu2 dev/urandom 24352 1 byte signed decimal integer, $ od -vAn -N1 -td1 dev/urandom -78 4 byte unsigned decimal integers, $ od -vAn -N4 -tu4 dev/urandom man od for more information on od.
Hi everyone and good morning :) .
i want to simply read from the linux file 'urandom' a random number and print it out on screen.just simple as that.
this function should be in a file called myrandom.c ( myrandom.h must be made also, which has my function dekleration ) . i will have to compile it later to a static libray and to dynamic library, and then write a main program which prints out 5 random numbers using the static library .
and another main program which prints out 5 random numbers using the dynamic library.
i wrote the myrandom.c code and myrandom.h code i dont know if they are correct .
i tested myrandom.c inside a main program and it gives me random number , but its very big .
ist that the right way to grap a random number from the urandom file?
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Dev Urandom Example C V
You're also using
printf incorrectly. When you are printing out the value of an int, printf does not want the address of that int. It wants the int itself.
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printf('%d', &rNumber); is wrong.
printf('%d', rNumber); is right.
WTF is going on with this?
It's still wrong.
str is effectively an
&str is an
*(&str) is an
int*. So you're doing exactly what you were doing before (wrongly providing an
int* when you …
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You need to
#include <stdio.h> to get the declaration of
fopen. As it is now you're implicitly declaring
fopen in a way that is incompatible with its definition. You should be getting a warning about that (and in C99 and later you should instead be getting an error that you're using a function without a declaration).
Once you do that, you should be getting another warning that you're implicitly converting the result of
int. That's because
fopen doesn't read anything from the file nor does it return an int.
fopen opens the file and then returns a file pointer. That file pointer can then be given to other file IO functions (like
fprintf etc.), which will actually read from or write to the file. Once you're done working with the file, you need to close it by passing the file pointer to
So no, you're not currently doing it correctly. The number you're printing is simply the numeric value of whichever pointer was returned by
fopen. It has nothing to do with the contents of the file.
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